How much ice would I have to store up in the winter in order to air condition my house all summer?
This is a great question... there's a lot to love about free air conditioning!
It certainly would be an easy system to build. All you need is a big insulated container (probably in the form of a hole in the ground) with some coiled tubes at the bottom. You would run a chilled water circuit from the container to a radiator inside the air conditioner. You would need a small pump to pump the water in the chilled water loop, but that's it.
So let's make a couple of assumptions:
- Let's assume that your air conditioner runs for 12 hours a day for three months out of the year.
- Let's assume that your house has a 5-ton air conditioner (60,000 BTU -- British thermal units).
- Let's assume that we can store the snow and ice with 50 percent efficiency. That is, over the course of the summer we will lose half of it to melting, inefficiencies in our system, etc.
- 60,000 BTU/hr * 12 hours/day * 90 days = 64,800,000 BTU
Multiplying by our 50 percent efficiency rating, let's call it 130 million BTU.
If you have a gram of ice at 32 degrees Fahrenheit (0 degrees Celsius), it will absorb 80 calories of energy converting from ice to liquid water. There are 252 calories in a BTU. So we need 3.15 grams of water to absorb 1 BTU of heat. The assumption here is that we are going to rely on the phase change from ice to water to power the air conditioner. Once all the ice melts, the water will warm up quickly.
So we need:
- 130,000,000 BTU * 3.15 grams/BTU = 409,500,000 grams of ice